Let the number of seats in section A be x, that of section B y and that of secyion C z. Then
x + y + z = 52000 . . . (1)
x = y + z . . . (2)
42x + 36y + 30z = 1960200 . . . (3)
Putting (2) into (1), gives
2x = 52000
x = 52000/2 = 26000
From (2) and (3), we have
y + z = 26000 . . . (4)
42(26000) + 36y + 30z = 1960200
36y + 30z = 1960200 - 1092000
36y + 30z = 868200 . . . (5)
(4) * 30 => 30y + 30z = 780000 . . . (6)
(5) - (6) => 6y = 88200
y = 88200/6 = 14700
From (4), z = 26000 - 14700 = 11300
Therefore, there are 26,000 seats in section A, 14,700 seats in section B and 11,300 seats in section C.
If G(x) = 39, then
5/2x - 7/2 = 39
Multiplying both sides by 2, we get
5x - 7 = 78
5x = 78 + 7
5x = 85
x = 17
I hope this answer helps!
3 X 567=1701 ....
so the two numbers are 1700 and 1702.....
Hope it helps !!!!
Answer:
Simplification of the expression (x−3)( x^2−4x−7) is x³ -7x² + 5x + 21 .
Step-by-step explanation:
As the expression given in the question be as follow .
= (x−3)( x²−4x−7)
simplify the above
= x (x²-4x-7)-3 (x²-4x-7)
Now open the bracket
= x³ - 4x² -7x - 3x² + 12x + 21
= x³- 4x²-3x²-7x + 12x + 21
= x³ -7x² + 5x + 21
Thus the simplification of the expression (x−3)( x^2−4x−7) is x³ -7x² + 5x + 21 .
