In probability, there is an equation appropriate for repeated trials. This concept is used to find the probability of an event happening when a number of a series of trials are done. The equation is:
n!/r!(n-r)! * p^(n-r) * q^r, where
n is the number of total number of trials
r is the number of success from the trials
p is the binomial probability of the event happening
q is equal to 1 - p
It is important to note that probability is a part of the whole. In this problem, we are to find the probability of at least one defect. That means it encompasses also the probability of 2, 3, and 4 defects. To be easier, let's just find the probability of no defect, then find subtract this to 1, to get the answer.
So, r=0 defects, n=4 trials, p = 10% defect rate, q = 90%. Substituting,
4!/0!(4-0)! * (0.1)^(4-0) * (0.9)^(0) = 0.0001
That means the probability of at least one defect is 1 - 0.0001 = 0.9999.
Answer: 0.075
Step-by-step explanation: when you are working with percentages to decimals you want to move the decimal two places to the left. If you are working with decimals and you want to make it a percentage you would move the decimal two places to the right.
Answer:
u prolly will know if u payed attention in class
Step-by-step explanation:
D=31.6 cm
r=31.6/2=15.8 cm
Area of circle= pi*r^2
A=pi*(15.8^2)
In terms of pi: A=249.6*pi cm^2
Using 3.14 as pi: A=783.9 cm^2