Evaluate the expression using x=-1 and y=3 6x^4y^3

Mathematics

2 answers:

frozen [14]3 years ago

8 0

Answer: 162

Look at attachment

anzhelika [568]3 years ago

3 0

Step-by-step explanation:

$6 {x}^{4} {y}^{3} \\ \\ = 6 \times ( - 1)^{4} \times (3)^{3} \\ \\ = 6 \times 1\times 27 \\ \\ = 162$

You might be interested in

A helicopter hovers at an altitude that is 1000 feet above a mountain of altitude 5210 feet. A second, taller peak is viewed fro

ehidna [41]

Given:

Height of Mountain A = 5210 feet
Distance of Mountain A from a helicopter above the peak = 1000 feet
Angle of depression:
Mountain B to helicopter = 43 degrees
Mountain B to Mountain A = 19 degrees

First, draw an illustration and label the enumerated given values.

Observe that there are two right triangles formed:

From the triangle formed by the helicopter and Mountain B,

let x = total height of mountain B
y = leg of first triangle (helicopter and mountain b)
h = hypotenuse
Use the Pythagorean Theorem:

cos (43) = y / h

From the second triangle formed by mountain b and a,

cos (19) = (1000 + y) / h

solve for h and y

then, solve for the height of Mountain B:

x = 1000 + y + 5210

6 0

3 years ago

Can someone find r please

katrin2010 [14]

Answer:

$r = 3 \times \sqrt{2}$

Step-by-step explanation:

The area of the square is 36.

A = s^2

36 = s^2

s = sqrt(36)

s = 6

The side of the square has length 6.

All sides of a square are congruent, so all sides have length 6.

If you extend segment JO to point L, you end up with segment JL which is a diameter of the circle and the diagonal of the square. We can use the Pythagorean theorem using two sides if the square as legs and the diagonal of the square as the hypotenuse of a right triangle.

a^2 + b^2 = c^2

6^2 + 6^2 = c^2

36 + 36 = c^2

c^2 = 72

$c = \sqrt{72}$