Question

Multiply the following polynomials and write the resulting polynomial in descending order. (3x-8)(2x^2+4x-9)

Answer 1

Answer:

The resulting polynomial is:

$6x^3-4x^2-59x+72$

Step-by-step explanation:

We have to multiply the polynomials:

$(3x-8)(2x^2+4x-9)\\\\=3x(2x^2+4x-9)-8(2x^2+4x-9)\\\\=6x^3+12x^2-27x-16x^2-32x+72\\\\=6x^3-4x^2-59x+72$

Hence, the resulting polynomial is:

$6x^3-4x^2-59x+72$

Answer 2

The product of the polynomial will be:
(3x-8)(2x^2+4x-9)
=3x(2x^2+4x-9)-8(2x^2+4x-9)
=6x^3+12x^2-27x-16x^2-32x+72
=6x^3-4x^2-59x+72

The answer: 6x^3-4x^2-59x+72