Answer:
Step-by-step explanation:
We have to select george but not nina with two other people
No. of ways selecting 2 two people knowing Geroge will be the third one is
(beacuse we have to exclude Nina)
And total no of ways of selecting 3 people out of 8 people is
Therefore the required Probability is
=
If SU bisects TSV, then TSU = USV
4y + 11 = 6y + 5
6y - 4y = 11 - 5 = 6
y = 6/2 = 3
Therefore, m<TSU = 4(3) + 11 = 12 + 11 = 23
Answer:
i dont think you have the full question here...
Answer:
If you roll two dices, you can get as results all numbers from 2 to 12. Among these, the prime numbers are 2, 3, 5, 7, 11. The probability you get each of them is: 2: you can get it only as 1+1, so one combination over 36 possibility. Probability: 1/36. 3: you can get it as 1+2 or 2+1, so two combinations over 36 possibility. Probability: 2/36. 5: you can get it as 1+4, 2+3, 3+2, 4+1, so four combinations over 36 possibility. Probability: 4/36. 7: you can get as 1+6, 2+5, 3+4, 4+3, 5+2, 6+1, so six combinations over 36 possibility. Probability: 6/36. 11: you can get it as 5+6 or 6+5 so two combinations over 36 possibility. Probability: 2/36. The total probability of getting a prime number is the sum of the probabilities, which is 15/36. So m=15, n=36 and 10m+n=150+36=186.
Answer:
(2.5 , 3.5)
Step-by-step explanation:
We can use the midpoint formula . Here the points are , (2,2) and (3,5) .
• <u>Using</u><u> </u><u>Midpo</u><u>int</u><u> Formula</u><u> </u><u>:</u><u>-</u><u> </u>
⇒ M = { (x1 + x2)/2 , (y1 + y2)/2 }
⇒ M = ( 2+3/2 , 5+2/2 )
⇒ M = ( 5/2 , 7/2 )
⇒ M = ( 2.5 , 3.5 )
<h3>
<u>Hence </u><u>the</u><u> </u><u>midpoint</u><u> </u><u>is</u><u> </u><u>(</u><u>2</u><u>.</u><u>5</u><u> </u><u>,</u><u> </u><u>3</u><u>.</u><u>5</u><u>)</u></h3>