Answer:
730 items
Explanation:
The objective of the given information is to determine the number of hamburgers UAHH should order for the following conditions:
Average daily demand 600
Standard deviation of demand 100
Desired service probability 99%
Hamburger inventory 800
The formula for a given order quantity in a fixed period of time can be expressed as :

where;
= order quantity = ???
= daily demand average = 600
L = lead time in days = 1
T = time taken = 1
z = no of standard deviation = ???
= standard deviation of usage in lead time and time taken = ???
I = present inventory level = 800
=
× standard deviation of daily demand
= 
= 1.4142 * 100
= 141.42 items
From the Desired service probability 99% = 0.99; we can deduce the no of standard deviation by using the excel function (=NORMSINV (0.99))
z = 2.33
From 



q = 729.5086 items
q ≅ 730 items
Therefore; the number of hamburgers UAHH should order from the following given conditions = 730 items
Answer:
is this a question? maybe you could give more context.
The multiplier applies to the investment, net exports and government spending.
<h3>What is a
multiplier?</h3>
This refers to an economic factor that of increased, it can causes an increases in many other related economic variables.
Hence, in economics, its applies to the investment, net exports and government spending.
Therefore, the Option A is correct.
Read more about multiplier
<em>brainly.com/question/19549086</em>
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Answer:
a) H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
b) t stat = -0.064
c) We will reject the Null hypothesis and the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
Explanation:
<u>a) stating the null and alternative hypothesis</u>
H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
<u>b) performing the test </u>
critical value = -2.88
T stat = coefficient / std error
= -0.02 / 0.31 = -0.064
c) From the test, the value of T stat > critical value we will reject the Null hypothesis hence the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
the answer is b message me if it is wrong