The amount of annual depreciation by the straight-line method is $18,800.
<h3>Annual depreciation</h3>
a. Annual depreciation
Annual depreciation=[($80,000 - $4,800) ÷ 4]
Annual depreciation=$18,800
b. Annual depreciation
Year 1 Annual depreciation= 10% × $80,000
Year 1 Annual depreciation = $8,000
Year 2 Annual depreciation= 10% × ($75,000 - $7,500)
Year 2 Annual depreciation = $7,520
Therefore the amount of annual depreciation by the straight-line method is $18,800.
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Answer:
$73.58
Explanation:
Total cost of product = $120
Total cost of product = Cost of material + Direct labor + Overhead
Cost of material = (3 * direct labor) - $6
Overhead = ¾ of Direct labor
Total cost of product = 3DL - $6 + DL + ¾ of DL
$120 = 3DL - $6 + DL + 0.75 DL
$126 = 4.75 DL
Direct Labor = 126/4.75
Direct Labor = $26.53
Material cost = 3 * $26.53 - $6
Material cost = $73.58
Answer:
16.25;
g(f(x)) ;
76 ;
f(g(x))
Explanation:
For 15 off
f(x) = x - 15
For 35% off
g(x) = (1 - 0.35)x = 0.65x
g(x) = 0.65x
A.)
For the $15 off coupon :
f(x) = x - 15
f(x) 40 - 15 = 25
For the 35% coupon :
g(x) = (1-0.35)x
g(x) = 0.65(25)
g(x) = 16.25
B.)
Applying $15 off first, then 35%
Here, g is a function of f(x)
g(f(x))
Here g(x) takes in the result of f(x) ;
For the $140 off coupon :
f(x) = x - 15
f(140) = 140 - 15 = 125
For the 35% coupon :
g(125) = (1-0.35)x
g(124) = 0.65(125) = $81.25
C.)
x = 140
g(x) = 0.65x
g(140) = 0.65(140)
g(140) = 91
f(x) = x - 15
f(91) = 91 - 15
f(91) = 76
D.)
Here, F is a function of g(x)
f(g(x))
f(x) = (0.65*140) - 15
