Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:
Neither.
Step-by-step explanation:
you are correct about the pattern, so it's not adding the same number and not multiplying by the same number. So it's neither.
This should help you on how to get the zeros and the answer for the bottom question is A
Answer:
Now, add these two equations.
You get,
Given,
You can test this to the other equation as well.
Hence, the two numbers are 14 and 10.
Answer:
is this the right question please??
