Hello :
<span>x² + y² + 14x + 2y + 14 = 0
(x²+14x)+(y²+2y)+14=0
(x²+2(7)(x) +7²) -7² +( y²+(2)(1)y+1²)-1² +14 = 0
(x+7)² +(y+1)² = 6²
the center : (-7,-1) and </span><span>length of the radius is : 6</span>
Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
Answer: okay so trying adding each part and count how many hours is 6 am and add and I hope you get it right if not I’m sorry for you- but you should find a more sure answer
Answer:
16
Step-by-step explanation:
Answer:
A. T= S+I
B. T= 325m+ 3600
C. T= 11,400
Step-by-step explanation:
