Answer:
6.7
Step-by-step explanation:
Given is a right angled triangle.
So by Pythagoras theorem:
Length of the third side
Are all equilateral triangles similar?
1 answer:
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I: x-2y>=8
II:2x+y<=3
start by isolating y on a side
with I:
x-2y>=8
-2y>=8-x
2y<=x-8
y<=x/2-4
with II:
2x+y<=3
y<=-2x+3
now you can draw I' and II' and read of the solutions with the graph.
transform the inequalities into lines in slope intercept form by replacing the inequality with equality:
y<=x/2-4
->
y=x/2-4
y<=-2x+3
->
y=-2x+3
look at the inequalities to figure out if the area above or below is valid for each line (y<=... -> area below is valid->colored in the attached image)
the area in which all areas overlap is the solution space.
II:2x+y<=3
start by isolating y on a side
with I:
x-2y>=8
-2y>=8-x
2y<=x-8
y<=x/2-4
with II:
2x+y<=3
y<=-2x+3
now you can draw I' and II' and read of the solutions with the graph.
transform the inequalities into lines in slope intercept form by replacing the inequality with equality:
y<=x/2-4
->
y=x/2-4
y<=-2x+3
->
y=-2x+3
look at the inequalities to figure out if the area above or below is valid for each line (y<=... -> area below is valid->colored in the attached image)
the area in which all areas overlap is the solution space.
Answer:
Therefore,
∠A = 30°
∠B = 60°
∠C = 150°
∠D = 120°
Step-by-step explanation:
Given:
A puzzle in the form of a quadrilateral is inscribed in a circle.
The vertices A ,B ,C ,D of the quadrilateral divide the circle into four arcs in a ratio of 1 : 2 : 5 : 4.
Let the common multiple be "x" then the angles will be
∠A = 1x
∠B = 2x
∠C = 5x
∠D = 4x
To Find:
The angle measures of the quadrilateral = ?
Solution:
In a Quadrilateral inscribed in a Circle,
Sum of the measure of all the angles in a Quadrilateral is 360°
Substituting the values we get
Therefore the measures are
∠A = 30°
∠B = 2 × 30 = 60°
∠C = 5 × 30 = 150°
∠D = 4 × 30 = 120°
Therefore,
∠A = 30°
∠B = 60°
∠C = 150°
∠D = 120°