Which is the focus of a parabola with equation y2 = 4x?

Mathematics

1 answer:

statuscvo [17]3 years ago

6 0

Answer:

(1, 0)

Step-by-step explanation:

Please write this as y^2 = 4x; the " ^ " indicates exponentiation.

The appropriate equation for a horizontal parabola that opens to the right is

y^2 = 4px

Here, we are told that y^2 = 4x; this tells us that 4p = 4, and so p = 1.

Again, this parabola is a horizontal one and it opens to the right. p = 1 is the distance of the focus from the vertex, and in this case p = 1. Thus, the focus is at (1, 0) (situated on the x-axis).

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30 Points! please help!

SVEN [57.7K]

Answer:

18) 4 * 10 ^ -10

19) t ^ 9

Step-by-step explanation:

18. When multiplying in scientific notation, just multiply the regular numbers together and add the exponents for the tens.

So it'll be 40 * 10^-11

However, the beginning number should have the decimal right after the 4, not any place after (for example, it's 3.056, not 30.56 or 3056.)

To fix this, move the decimal place forward one space from 40. to 4.0, and add 1 to the -11 power.

So the answer is now 4 * 10^-10

19. When dividing exponents, if the base number is the same, you can divide. (Basically, you can not divide x^2 and y^3 because x and y aren't the same)

Since in this case it's t, you can divide.

Dividing exponents is simple: just subtract them.

14 - 5 = 9

so the answer is t ^ 9

3 0

4 years ago

Perform the indicated operation and simplify the result. (Tell me if it’s too blurry)

Alex

Answer:

7/(3a-1)

Step-by-step explanation:

I have tried to show the steps in the attached image,