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nevsk [136]
3 years ago
13

Which is the focus of a parabola with equation y2 = 4x?

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0

Answer:

(1, 0)

Step-by-step explanation:

Please write this as y^2 = 4x; the " ^ " indicates exponentiation.

The appropriate equation for a horizontal parabola that opens to the right is

y^2 = 4px

Here, we are told that  y^2 = 4x; this tells us that 4p = 4, and so p = 1.  

Again, this parabola is a horizontal one and it opens to the right.  p = 1 is the distance of the focus from the vertex, and in this case p = 1.  Thus, the focus is at (1, 0) (situated on the x-axis).

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A student got 68% of the questions correct on the Social Studies test. If there were 50 questions, how many questions did they g
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Answer:

The answer is 34.

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3 years ago
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A sample of 16 items from population 1 has a sample variance 5.8 and a sample of 21 items from population 2 has a sample varianc
Nady [450]

Answer:

Reject the null hypothesis.

Step-by-step explanation:

n1 = 16

n2 = 21

S.V1 = 5.8

S.V2 = 2.4

\alpha = 0.05

H_{0} = Population Variance 1 ≤  Population Variance 2

H_{a} = Population Variance 1 >  Population Variance 2

Test statistic value = 5.8 / 2.4 = 2.417

Degrees of freedom is n - 1

15 and 20

Critical value is F_{0.05} = 2.2

2.417 > 2.2

we reject the null hypothesis as the critical value is greater than the test statistic.

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3 years ago
A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
netineya [11]

Answer:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

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3 years ago
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A) 6
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Find the surface area
Zinaida [17]

Answer:5400

Step-by-step explanation:

A= 6a*2

6x9x10*2= 5400

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