Y'sinx=ylny, is equivalent to <span>dy / dx (sinx=ylny, and </span><span>dy sinx=ylny dx
it is similar to dy/</span>ylny = dx/sinx
so integral (dy/ylny = integral dx/sinx)
integral dx/sinx)= Ln{abs value ( tan(x /2 + pi /4)}
integral (dy/ylny= ln(lny)
final answer is lny = {abs value ( tan(x /2 + pi /4)}+C, you can find y, or x
Answer:
B
Step-by-step explanation:
it is an exponential function
Answer:
No. It is a constant function.
Step-by-step explanation:
The function f(x) = e^2 is not an exponential functional. Rather, it is a constant function. The reason for this is that in f(x) = e^2, there is no x involved on the right hand side of the equation. The approximate value of e is 2.718281, and the approximate value of 2.718281^2 is 7.389051. This means that f(x) = e^2 = 7.389051. It is important to note that for any value of x, the value of the function remains fixed. This is because the function does not involve the variable x in it. The graph of the function will be a line parallel to the x-axis, and the y-intercept will be 7.389051. For all the lines parallel to x-axis, the value of the function remains the same irrespective of the value of x. Also, the derivative of the function with respect to x is 0, which means that the value of the function is unaffected by the change in the value of x!!!
