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Alexeev081 [22]
3 years ago
13

What is the slope of a line that is perpendicular to the line y = 1?

Mathematics
2 answers:
Andrews [41]3 years ago
5 0
I think the answer is x=any real number
mote1985 [20]3 years ago
5 0
Check the picture below

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Point A (4,-3) is reflected over the y- axis. What are<br> the coordinates of A'?
yan [13]

Answer:

A'(-4,-3)

Step-by-step explanation:

use formula of reflection over y axis

(x,y)=(-x,y)

A(4,-3)=A'(-4,-3)

5 0
2 years ago
Read 2 more answers
a math student is standing 40 feet from the base of a water tower. the angle of elevation from her horizontal line of sight is 7
Lerok [7]

9514 1404 393

Answer:

  128 ft

Step-by-step explanation:

The height of the tower above eye-height is related to the angle by ...

  Tan = Opposite/Adjacent

  tan(72°) = (tower height above eye height)/(40 ft)

  tower height above eye height = (40 ft)×tan(72°) = 123 ft

Since eye height is 5 ft, the total height of the tower from the ground is ...

  tower height = eye height + height above eye height

  tower height = 5 ft + 123 ft

  tower height = 128 ft

4 0
2 years ago
Impossible question for me plz help
klio [65]

Answer:

The line x = 3 is simply a vertical line that passes through every single point where x is equal to 3.

One that is is parallel and passes through (-4, 7) will be in the same format, just with another number.  The given point has an x-coordinate of -4, so the line is:

x = -4

8 0
2 years ago
Ten is 5% of what number?
Karo-lina-s [1.5K]

Answer:

200

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If f(x) = -7x + 1 and g(x) = Square root of x-5,<br> what is (fºg)(41)?
Ghella [55]

This is similar to the other question you posted. Follow the same steps as before.

First find g(41).

g(41) = sqrt{x - 5}

g(41) = sqrt{41 - 5}

g(41) = sqrt{36}

g(41) = 6

We now find f(6).

f(6) = -7(6) + 1

f(6) = -42 + 1

f(6) = -41

Answer:

(fºg)(41) = -41

Did you follow?

6 0
2 years ago
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