Katie won't have more than 100 shells until the 7th day
Put a point H on (9, 2). Sketch a triangle out of the three points. Distance between (-2, 2) and (9, 2) is going to be 11. Distance between (9, 2) and (9, 5) is going to be 3. These correspond to the a and b of the Pythagorean Theorem
c^2=a^2+b^2
c=√11^2+3^2=√130
<span>Square root of 130 is 11.4</span>
Answer:
B. 2 (Second Option)
Step-by-step explanation:
Four times: ⇒ 4
Number:⇒ y
4y+3=11
<em>Subtract by 3 both sides of equation.</em>
<em>4y+3-3=11-3</em>
<em>Simplify.</em>
<em>11-3=8</em>
<em>4y=8</em>
<em>Divide by 4 both sides of equation.</em>
<em>4y/4=8/4</em>
<em>SImplify, to find the answer.</em>
<em>8/4=2</em>
<em>y=2 is the correct answer.</em>
<em>2 is the correct answer.</em>
Y = 30/20x + 20
( i haven’t done this in a while but i’m pretty sure this is right)
Answer:
Step-by-step explanation:
Given that

To find tangent, normal and binormal vectors at (0,0,1)
i) Tangent vector

At the particular point, r'(t) = (1,1,e)
Tangent vector = 
ii) Normal vector
T'(t) = 
At that point T'(t) = (0,0,e)/e = (0,0,1)
iii) Binormal
B(t) = TX N
= ![\left[\begin{array}{ccc}i&j&k\\1&1&e^t\\0&0&e^t\end{array}\right] \\= e^t(i-j)](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%26e%5Et%5C%5C0%260%26e%5Et%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%20e%5Et%28i-j%29)