From the calculations, the rate of growth of the culture is 2.88.
<h3>What is exponential growth problem?</h3>
We apply the exponential growth problem when there is an exponential increase.
Thus, we have; P =Poe^rt
P = amount at time t
Po = amount originally present
t = time taken
r = rate of growth
1.6 × 10^6 = 16e^4r
1.6 × 10^6/16 = e^4r
1.0 * 10^5 = e^4r
ln 1.0 * 10^5 = ln e^4r
11.5 = 4r
r = 11.5/4
r = 2.88
Learn more about exponential growth:brainly.com/question/11487261
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<span>Plant and animal cells have different structures. One structural difference of plant cells and animal cells is the presence of the plant cell’s </span>cell wall,<span> specialized plastids and a large central vacuole which are not found within animal cells.
Another difference is the garbage disposal of each cell. Centrosomes and lysosomes are found in animal cells but both do not exist within plant cells. The animal cell’s garbage disposal takes place in the lysosome while garbage disposal of plant cells takes place in the vacuole.</span>
Answer: I'd say the answer would be (A)
Explanation:Depending on the Anphibian, they breathe through their lungs and skin at first and develope Gills later in life. Some are born with gills and lungs. But normally they start with lungs first.
After fertilization of the ovule, the megaspore develops into the food supply of the mature seed.
After fertilization of the ovule, the <em />integument develops into the seed coat.
After fertilization of the ovule, the fertilized egg develops into the embryo of the mature seed.
The ovule contains the female reproductive cells of the seed plants and when fertilized, it produces the seed. Ovules contain megasporocytes, cells that produce megaspores through cell division. An integument is a layer that protects and surrounds the ovule. After fertilization, the integument protects and surrounds the seed. After fertilization, the ovule contains a diploid zygote which develops into an embryo.
