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Katena32 [7]
3 years ago
12

Which of the following is a hazard associated with driving at high speeds?

SAT
2 answers:
Dominik [7]3 years ago
7 0
B. small steering gestures cause exaggerated motions.
Solnce55 [7]3 years ago
5 0
The answer is B! Even the smallest gestures can be exaggerated to the point of causing an accident, so always be cautious when/if you have to drive at high speeds. I hope this helps :)
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a grocery store owner may choose to remain a sole proprietorship because he most likely wnts. help with decision making / to ope
Mazyrski [523]
Is this supposed to be a fragment or sentence type of question? If so
It’s fragment
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In order to get good results in relation to observing water pressure at fixtures, it is good inspection procedural practice to i
Lana71 [14]

In order to get good results in relation to observing water pressure at fixtures, it is good inspection procedural practice to inspect the plumbing fixtures at the "pressure gauges"

<h3>What is plumbing fixtures?</h3>

Plumbing fixtures are the devices that can be linked with a plumbing system to deliver fluid or drain it.

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It is common practice for these system to be fitted with a pressure gauges.

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6 0
1 year ago
What are the terms in the exponential expression 5e^3x+1+2
natima [27]

Answer:

5e ³ x+1+2(solution) terms are 5e5e ³ x,1,1, 2.

Explanation:

A term is a single mathematical expression. It may be a single number (positive or negative), a single variable ( a letter ), several variables multiplied but never added or subtracted. Some terms contain variables with a number in front of them. The number in front of a term is called a coefficient. Does it make more sense?

5 0
2 years ago
Hallie has two tasks both due on the same day: math homework and a short English essay. Which should she start on first to make
pantera1 [17]
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7 0
3 years ago
Read 2 more answers
B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len
Citrus2011 [14]

Answer:

The additional words is 2^n

Explanation:

Given

B(n) = 2^n

Required

Determine the additional words; i.e. B(n + 1) - B(n)

From the given parameters, we have that;

B is a function of n

Such that;

B(n) = 2^n

To calculate B(n+1), we simply substitute n + 1 for n

B(n) = 2^n

B(n + 1) = 2^{n + 1}

Applying laws of indices

B(n + 1) = 2^{n} * 2^1

B(n + 1) = 2^{n} * 2

B(n + 1) = 2(2^{n})

Calculating Additional Binary Code;

B(n + 1) - B(n)

Substitute values for B(n + 1) and B(n)

B(n + 1) - B(n) = 2(2^n) - 2^n

Express 2^n as 2^ n * 1

B(n + 1) - B(n) = 2(2^n) - 2^n * 1

Express 1 as 2^0

B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0

Factorize

B(n + 1) - B(n) = 2^n(2 - 2^0)

B(n + 1) - B(n) = 2^n(2 - 1)

B(n + 1) - B(n) = 2^n(1)

B(n + 1) - B(n) = 2^n

Hence, the additional words is 2^n

8 0
3 years ago
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