By conservation of momentum,
(900 kg) (15.0 m/s) i + (750 kg) (20.0 m/s) j = (900 kg + 750 kg) v
where v is the velocity vector of the combined cars. Solve for v :
(13,500 i + 15,000 j) kg•m/s = (1650 kg) v
v ≈ (8.18 i + 9.09 j) m/s
Then the direction of v relative to East is θ such that
tan(θ) ≈ 9.09/8.18 ⇒ θ ≈ 48.0°
so the wreckages would move at approximately 48.0° north of east.
Answer:
improved energy production
Explanation:
Answer:
54
Explanation:
First write the list of numbers which the tens number is one less then ones place.(21,32,43,54,65,76,87,98). Remember this list then add the digits together. If you know your multiplication, the first 5 should be easy to solve so multiple the sum you received from adding the numbers by 6 until you get to one with the same starting number
(21)2+1= 3 x 6= 18
(32)3+2= 5 x 6= 30
(43)4+3= 7 x 6= 42
(54)5+4= 9 x 6= 54
(65)6+5=11
(76)7+6=13
(87)8+7= 15
(98)9+8 = 17
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