There are no obtuse angles
So 2.5^2= 1.5^2 +b^2
6.25= 2.25 +b^2
Subtract 2.25 on each side
4= b^2
Take the square root of each side
X=2
Hope it helps
Answer:
it's confusing. you didn't drop the question propeely
9514 1404 393
Answer:
cos(θ) = -12/13
csc(θ) = -13/5
Step-by-step explanation:
The relation between the cot and csc is ...
cot² + 1 = csc²
The signs of the cot and sec tell you this is a 3rd quadrant angle, where cos and csc are both negative.
Then ...
csc(θ) = -√(1 +(12/5)²) = -√(169/25)
csc(θ) = -13/5
__
cos(θ) = cot(θ)/csc(θ) = (12/5)/(-13/5)
cos(θ) = -12/13
Given:
Probability that both lights are red 0.55
Probability that 1st light is red 0.69
Find the probability that the 2nd light is red, given that the first light is red.
0.55/0.69 = 0.797 or 0.80
The probability that the 2nd light is red while the 1st light is also red is 0.80.
