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3 years ago

find the smaller of 2 consecutive integers,x, if the sum of the smaller and 6 times the larger is -29

Mathematics

1 answer:

AnnyKZ [126]3 years ago

3 0

Answer:- The smaller integer is -5.

Explanation:-

Let the first consecutive integer be x and the second consecutive integer be x+1.

According to the given question:-

x+6(x+1)= -29

⇒x+6x+6= -29 [distributive law]

⇒x+6x= -29-6 [subtract 6 on the both sides]

⇒7x= -35 [combining like terms ]

⇒x= -5 [dividing 7 on both sides]

Thus the smaller integer =x= -5

larger integer =x+1= -5+1= -4

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A backyard pool has a concrete walkway around it that is 3 feet wide on all sides. The total area of the pool and the walkway is

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<h2>29.4 length and 21.4 width.</h2>

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In addition, we know that the total area is 970 and the length is 8 ft longer than the width ( $L=W+8$ ). So:

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