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3 years ago

Solve 3(x+1) -2x= -6

1 answer:

s2008m [1.1K]3 years ago

6 0

3(x + 1) - 2x = -6 |use distributive property: a(b + c) = ab + ac

3x + 3 - 2x = -6

x + 3 = -6 |subtract 3 from both sides

x = -9

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(7,-4);

olga_2 [115]

Literally just plug it in

6(7) + 5(-4) - 42 = 0

42 -20 -42 = 0

-20 = 0

Not a solution.

8 0

3 years ago

What is the surface area of a cube with a side length of 5 inches?

LenaWriter [7]

The surface area of the cube is 150 in^2

Further Explanation:

A cube is a six-faced figure with same side length.

The formula for calculting the surface area of cube is given by:

$SA = 6s^2$

Here s is the length of side.

Given

Side length =s =5 in

$SA=6*(5)^2\\= 6*25\\=150\ in^2$

The area of cube is 150 in^2

Keywords: Surface area, Cube

Learn more about cube at:

#LearnwithBrainly

7 0

3 years ago

What is the vintercept of the line whose equation is y= 1/2x-3

klemol [59]

Answer:

The y-intercept of line is (-3)

Step-by-step explanation:

Given equation of line is given by y= $\frac{1}{2}x-3$

The general equation of line is given y=mx+c

Where, m= slope of line

c= y-intercept of line

On comparing both the equation.

c=(-3)

y-intercept is when x=0,

therefore,

y= $\frac{1}{2}x-3$

y= $\frac{1}{2}(0)-3$

y=(-3)

Thus, y-intercept of line is (-3)

8 0

3 years ago

Checking the Mean Value Theorem:<br><br>Number 3

mrs_skeptik [129]

$\bf f(x)=x+\cfrac{1}{x}\qquad \left[\frac{1}{2},2 \right]\\\\
-----------------------------\\\\
\cfrac{df}{dx}=1+\left(-1x^{-2} \right)\implies \cfrac{df}{dx}=1-\cfrac{1}{x^2}
\\\\\\
f'(c)=1-\cfrac{1}{c^2}\quad \quad 1-\cfrac{1}{c^2}=\cfrac{f(2)-f\left( \frac{1}{2} \right)}{2-\frac{1}{2}}
\\\\\\
1-\cfrac{1}{c^2}=\cfrac{\frac{5}{2}-\frac{5}{2}}{\frac{3}{2}}\implies 1-\cfrac{1}{c^2}=\cfrac{0}{\frac{3}{2}}\implies 1-\cfrac{1}{c^2}=0
\\\\\\
1=\cfrac{1}{c^2}\implies c^2=1\implies c=\pm\sqrt{1}\implies c=\pm 1$

there's a quick graph below of the bounds and the tangent at "c"

not happening -2 or 2 will have a tangent parallel to a,b, needless to say -2 is out of the range [a,b] anyway, so the only value is really 1, on the positive 1st quadrant

6 0

3 years ago

Arianna correctly simplified an expression. When she substituted mc020-1. Jpg into the simplified expression, the value was â€"4

9966 [12]

Answer:

value was â€"4. Which could be Ariannaâ€™s original expression? One-sixth (negative 3 x minus 24) One-sixth (negative 5 x minus 8) One-sixth (negative 10 x minus 4) One-sixth (negative 12 x minus 16).

6 0

3 years ago