Question

Pls help!!will give the brainliest!Need explanationUrgent!!!​

Answer 1

Answer:

h=4 and k=-4....

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$A^2= \begin{bmatrix} 4 & 0 \\ 4 & 4 \end{bmatrix}$

Equate this to $hA + kI$

Thus,

$A^2= h \begin{bmatrix} 2 & 0 \\ 1 & 2 \end{bmatrix} + k \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$

Hence we have the following equations (by equating corresponding terms on both sides):

$2h+k=4$

$h=4$

Solve these to get $h=4$ and $k=-4$