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alekssr [168]
3 years ago
11

Need help with please

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0
45 degrees I’m pretty sure. Sorry if I’m wrong
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Given f(x) = -4x - 2, solve for x when f(x) = 6.
Andrej [43]

Answer:

use

Step-by-step explanation:

calculator

6 0
3 years ago
Two workers produced 86 parts and the first one produced 8 more parts than the second one. How many parts did each worker produc
Diano4ka-milaya [45]
1st worker produced x pants,
2nd worker produced (x+8) pants.

x+x+8=86
2x=78
x= 39

x+8 = 
39+8 = 47

1st worker produced 39 pants,
2nd worker produced 47 pants.
6 0
4 years ago
Read 2 more answers
Jorge makes 59.50 an hour for working at a Shoe Store. He wants to buy a skateboard that costs $110,00. How many hours must Jorg
siniylev [52]

Answer:

2 hours

Step-by-step explanation:

Since he gets 59.50 every hour you'll need to see how much 59.50 can go into 110$

So, 110/59.50 = 1.8487395

You can then round this number up.

Since he's paid by the hour he'll need to work 2 hours but he'll still have a bit of money left over

4 0
3 years ago
Lisa bought 5/8 of trail mix she give 1/8 pound of trail mix how much trail mix does lisa have left
Reil [10]
Supposing that the trail mix was 5/8 pound, and Lisa gave 1/8 pound, then to know what is left we only have to subtract those fractions:
5/8 - 1/8 = 4/8
that is because we only subtract the numerators (upper part) of the fractions due to the fact that the denominators are equal, now, 4/8 can also simplify to 1/2
therefore there are left 4/8 pound of trail mix or, what is the same, 1/2 pound of it
4 0
4 years ago
Read 2 more answers
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
blagie [28]

Answer:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

Step-by-step explanation:

For this case we can define the variable of interest amount of Pb209 and for the half life would be given:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

4 0
3 years ago
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