Question

Solve (factorise ).​

Answer 1

Answer: (1)  x²y (2) 7pqr  (3) a  (4) 6a²  (5) y³z²

Step-by-step explanation:

(1)  x^4y³ and x²y

     x^4y³ =  x²y(x²y²)

    x²y      = x²y

Therefore the Highest Common factor

               x²y which is the common factor.

(2) 14p²qr^4 = 2 x 7 x p² x q  x r^4

   49p²q²r    = 7 x 7 x p² x q² x r

   35pqr       = 5 x 7 x p x q x r

Therefore HCF =  7 x p x q x r

                         = 7pqr

(3) -a^5             = -( a x a x a x a x a )

                         = -(a^5)

       ab³            =   a x b x b x b

Therefore HCF =   a

(4)   6a²             = 2 x 3 x a x a

      -18a6          = -( 2 x3 x 3 x a x a x a x a x a x a)

     -12a²            = -( 2 x 2 x 3 x a x a )

Therefore HCF  = 2 x 3 x a²

                          = 6a²

(5)   3y³z²           = 3 x y x y x y x z x z , 3 x y³ x z²

      15y^4z²       =  3 x 5 x y x y x y x y x y x z x z, 3 x 5 x y^4 x z²

      y^6z³          = y^6 x z³

Therfore HCF  = y³ x z²

                         = y³z²