The problem in the picture would be
x^2+10x+21
You can work out the percentage change and that would help you work out the rate of appreciation :)
The formula is ((new value - old value)/old value) * 100.
So you do 
Therefore the rate of appreciation is 8% p/a.
Answer:
the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds
Step-by-step explanation:
The computation of the number of seconds that you and your friend would be have the similar distance from the starting line is shown below:
As we know that
Speed = Distance ÷ Time
SO,
Time = Distance ÷ speed
= 10 meters ÷ difference in speed
= 10 meters ÷ (6 meters per second - 5.5 meters per second)
= 10 meters ÷ 0.5 meters per second
= 20 seconds
hence, the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds
Step-by-step explanation:
the expression 5²=25
i hope this is helpful.
