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Natalija [7]
2 years ago
14

Helpp please :)) Explain how you got the answer too, so I understand how to solve.

Mathematics
1 answer:
Lana71 [14]2 years ago
8 0
4 by x is the answer
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Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)
BigorU [14]
For a moment, let y=x^2-2x+5. Then by the distributive property,

(2x^2+4x-3)p=2x^2p+4xp-3p


Again by the distributive property,

2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2

4xp=4x(x^2-2x+5)=4x^3-8x^2+20x

-3p=-3(x^2-2x+5)=-3x^2+6x-15

Taking everything together, we get

(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)
(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15
7 0
3 years ago
Read 2 more answers
A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
Vanyuwa [196]

Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

Given:

A rectangle with 13 x 26 dimensions

And corners are cut to form side squares.

To Find:

Maximum possible volume for box

Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

Formulating the volume equation for the box

So corner square sides we are going to fold up which makes height of the box

and remaining part will be length and breadth

As shown in fig,

Length=26-x

breadth=13-x

And height will be x

V(x)=x*(26-x)*(13-x)

To get maximum volume differentiate the above equation,

V(x)=x*(26*13-26*x-13*x+x^2)

V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

V''(x)=6x-78

Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

x=[-b±(b^2-4ac)^1/2]/2a

x=[78±Sqrt[(78)^2-4*338*3)]/2*3

x=[78±Sqrt(3028)]/6

x=[78±55.027]/6

x=78+55.027/6 or x=78-55.027/6

x=22.17  or x=3.8288

Use these values in 6x-78 to know which value posses the max and min value for the function.

So when x=22.17

6x-78=6*22.17-78

=55.02>0  i.e function will have minimum value .

When x=3.8288

6*3.8288-78

=-55.0272<0 i.e. Function will have maximum value

Now, the function will defines the maximum volume

V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

V(x)=778.53 C.C

6 0
3 years ago
Carlos buys a new bicycle
Bond [772]
16% of 231 is 36.80
16% + 84% = 100%
36.80+ 231 = $267.80
Ans = $267.80
3 0
3 years ago
If there are 360 g of radioactive material with a half life (decreased by half or 50% )of 1 hour, how much of the radioactive ma
Lostsunrise [7]

After 1 hour, 360 g decays to 180 g.

After another hour (total 2 hours), 180 g decays to 90 g.

After another hour (total 3), 90 g decays to 45 g.

After one more (total 4), 45 g decays to 22.5 g.

More quickly, with a half-life of 1 hour, the 360 g of starting material decays to

(360 g) / 2⁴ = 22.5 g

In general, if the half-life is 1 hour, then after <em>n</em> hours, an initial amount <em>A</em> of this substance decays according to

<em>A</em> / 2<em>ⁿ</em>

5 0
3 years ago
Find FC<br><br> A. 10.6<br> B. 12.6<br> C. 14<br> D. 180<br><br><br><br> Helppppppp ASAP please
Cloud [144]
The answer is 12.6 for sure
6 0
3 years ago
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