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2 years ago

Please help me! 30 points!

Mathematics

2 answers:

VladimirAG [237]2 years ago

8 0

Answer:

vertical asymptote at x=2

Step-by-step explanation:

f(x) = 1/4 ln(x-2) +3

We know that ln(x) has an asymptote at x=0

This function is shifted to the right 2 and up 3,

The x asymptote will be shifted to the right 2

x=0 +2

x=2

Galina-37 [17]2 years ago

6 0

Answer:

Vertical asymptote at x = 2

Step-by-step explanation:

ln is only valid for positive inputs

Its undefined for 0 and negative, i.e.

x - 2《0

x《2

So asymptote is

x = 2

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Read 2 more answers

Please I need help with this!!!!!!!

inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

$x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}$

$x=\sqrt[3]{5^4}$ [Since, $a^{\frac{1}{3}}=\sqrt[3]{a}$ ]

$x=\sqrt[3]{5\times 5\times 5\times 5}$

Step 5:

$x=\sqrt[3]{(5)^3\times 5}$

$x=\sqrt[3]{5^3}\times \sqrt[3]{5}$

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

$(3x-1)^{\frac{1}{5}}=2$

Step 1:

$(3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}$

Step 2:

$(3x-1)=2^5$

Step 3:

$3x=32+1$

Step 4:

$x=11$

4). By substituting $x=11$ in the original equation.

$(3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}$

$=(2^5)^\frac{1}{5}$

$=2$

There is no extraneous solution.

3 0

2 years ago