Question

A jewelry designer is making a pendant. The pendant will be a circular dis (center O) with a circular hold cut out of it, as shown. The radius of the disc is 35 millimeters. Find the area of the pendant. Use 3.14 for π and round to the nearest tenth

Answer 1

Answer:

2884.8 millimeters squared

Step-by-step explanation:

Given:

The radius of the disc is 35 millimeters, so the area of it is:

π$r^{2}$ = 3.14*$35^{2}$ = 3846.5

Then, we find out the area of the circular hold cut out of the bigger one, its radius is a haft of the radius of the bigger circle = 35/2 = 17.5

π$r^{2}$ = 3.14*$17.5^{2}$ =961.6

=>  the area of the pendant = 3846.5  - 961.6  =2884.8 millimeters squared