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lesantik [10]
3 years ago
10

A jewelry designer is making a pendant. The pendant will be a circular dis (center O) with a circular hold cut out of it, as sho

wn. The radius of the disc is 35 millimeters. Find the area of the pendant. Use 3.14 for π and round to the nearest tenth

Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:

2884.8 millimeters squared

Step-by-step explanation:

Given:

The radius of the disc is 35 millimeters, so the area of it is:

πr^{2} = 3.14*35^{2} = 3846.5

Then, we find out the area of the circular hold cut out of the bigger one, its radius is a haft of the radius of the bigger circle = 35/2 = 17.5

πr^{2} = 3.14*17.5^{2} =961.6

=>  the area of the pendant = 3846.5  - 961.6  =2884.8 millimeters squared

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hodyreva [135]
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========================================================

Explanation:

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The top most angle is given as D = 65. Note how the angles D and E are opposite the congruent lines (marked with the red single tickmarks). This means that angles D and E are congruent to one another. So E = 65 as well. This is shown in the diagram below.

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So angle DCE is 50 degrees.

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Now we move onto triangle ABC.

Because angles DCE and ACB are vertical angles, this makes angle ACB 50 degrees also. Effectively, anywhere you see a 'y' in the diagram below, replace it with 50.

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The answer is D.

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