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3 years ago

13

Sorry for the bad picture quality, lol trust me I’m not android user... bUt I really am struggling! Help!-

1 answer:

Klio2033 [76]3 years ago

3 0

Answer:

a to u

Step-by-step explanation:

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Williiam lost 25% of his marble,gave 1/6 of the remainder to his.Brother and had 120 marbles left.How many marbles did he have a

bija089 [108]

Answer:

Number of marbles with Williams at the starting = 192

Step-by-step explanation:

Let total number of marbles with Williams = m

He lost marbles = 25% of the total number

= $\frac{25}{100}\times m$

= $\frac{m}{4}$

Remaining marbles with Williams = m - $\frac{m}{4}$

= $\frac{3m}{4}$

He gave marbles to his brother = $\frac{1}{6}$ th of the remaining marbles

= $\frac{1}{6}\times \frac{3m}{4}$

= $\frac{m}{8}$

Remaining marbles after giving marbles to his brother = 120

Therefore, $\frac{3m}{4}-\frac{m}{8}=120$

$\frac{6m}{8}-\frac{m}{8}=120$

$\frac{5m}{8}=120$

m = $\frac{120\times 8}{5}$

m = 192

Number of marbles with Williams at the starting = 192

5 0

3 years ago

How many 1/5 s make 14/10

Sliva [168]

Answer:

$7$

Step-by-step explanation:

$\frac{14}{10} \div \frac{1}{5} = 7$

8 0

2 years ago

Read 2 more answers

John purchased a carr in 1961 for $12,000. Experts estimate that its value will increase by 5% per year. How much will be the co

dexar [7]

Answer:

B

Step-by-step explanation:

I'm super lazy rn and it doesn't need explanation

5 0

3 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

<u>Finding P(A)</u>

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

<u>Finding P(B)</u>

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

<u>Finding $P(A \cap B)$ </u>

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago

Get all of them and get brainliest

Marina86 [1]

1. 21,150
2. 2.5193
3. 27.98
4. 11,100

8 0

3 years ago