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almond37 [142]
3 years ago
11

The width of a rectangle is represented by 5 + 2y the lingth is twice as long as the width.What is the perimeter of the rectangl

e?Select all correct expressions
Mathematics
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

30+12y

Step-by-step explanation:

width=5+2y

length is twice its width

so 2(5+2y)=10+4y

perimeter=L+W+L+W

=2(L+W)

Therefore 2(5+2y+10+4y)

10+4y+20+8y

collect the like terms together

10+20+4y+8y

30+12y

so the answer=30+8y

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60 is what percent of 48?
Yakvenalex [24]

Answer:

80%

Inverted = 125%

Step-by-step explanation:

Simplify the fraction to the most simpliest number, which is 4/5. 4/5 = 80%.

If it’s inverted (as in 60/48), the most simpliest number is 5/4. 5/4 = 125%.

7 0
3 years ago
Read 2 more answers
To rent a jet ski at Hayden’s cost is $25 plus $3 per hour. At Austin’s, it costs $5 plus $8 per hour. At how many hours will th
Katen [24]
<u>At Hayden's:</u> 

(25+3)= \ 28+3 \ (2nd \ hour)=31+3 \ (3rd \ hour)=34+3 . . . \swarrow\swarrow \\ \ \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow  \boxed{34+3=37}= \ (4rth \ Hour)

<u>At Austins:</u> 

(5+8)= \ (first \ hour) = 13+8= \ 21 = (2nd \ hour) \ 21+8=29= \ \swarrow \\ \longrightarrow \ 29=(3rd \ hour)=\boxed{ 29+8= (37)= \ ((Forth \ hour))}

As we can see in both results, it would take them (4 hours) for the prices to be equaled.
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28
Nataliya [291]
Assuming you mean

5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t

This ODE is linear in y, and you can already contract the left hand side as the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t

Integrating both sides with respect to t yields

5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt
5y\sin t=\dfrac13\sin^3t+C
y=\dfrac1{15}\sin^2t+C\csc t

Given that y\left(\dfrac\pi2\right)=9, we have

9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2
9=\dfrac1{15}+C
C=\dfrac{134}{15}

so that the particular solution over the interval is

y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t
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Well it think the answer is D.98
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