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Masteriza [31]
4 years ago
9

I have a goal to drive two miles at an average rate of 60 miles per hour. During the first mile you travel at a rate of 30 miles

per hour. How fast would you need to travel during the second mile in order to reach your goal of 60 miles per hour.
Mathematics
1 answer:
Marta_Voda [28]4 years ago
3 0
You would need 2 hours
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On the set of axes below. solve the following
Delvig [45]

Answer:

i think x=1 y=3 (1,3)

Step-by-step explanation:

2x+4x-1 = 5

x = 1

y = 4x-1

y = 4(1)-1

y = 4-1

y = 3

5 0
3 years ago
Find the sale price when the original price is $91.00 and the discount rate is 13%
AleksandrR [38]

Answer:

$79.17

Step-by-step explanation:

91.00 x 0.13= 11.83 (the discount)

91.00-11.83= $79.17 (the sale price)

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Find the area of the shape shown below. NEED HELP ASAPPPPPPPPP
Fittoniya [83]
Answer: A = 7 unit^2

Explanation:

First let’s cut the shape into 1 square and 1 trapezoid.

After that we can calculate the 2 polygons individually

Find area of square:

A = 2 x 2 = 4

Find area of trapezoid:

A = (2 + 1)2/2 = 3

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7 0
3 years ago
I need help with numbers 7-9 please
jolli1 [7]

Answer:

C

5(10)+10=60

-2(-5)+7=17

Step-by-step explanation:


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3 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
2 years ago
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