9514 1404 393
Answer:
maximum: 8; no minimum
Step-by-step explanation:
A graph can be useful. I find a graphing calculator handy. It shows the maximum of the function is f(-1) = 8. Since the parabola goes to -∞ for large values of x, there is no minimum.
maximum: 8
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You can also find the maximum by putting the function in vertex form.
-3(x^2 +2x) +5 . . . . factor the leading coefficient from the x terms
-3(x^2 +2x +1) +5 -(-3)(1) . . . . add the square of half the x-coefficient, subtract the equivalent amount
-3(x +1)^2 +8 . . . . . . the vertex form of the expression for f(x)
This form is ...
a(x -h)^2 +k . . . . . with a=-3, h=-1, k=8
so the vertex is (h, k) = (-1, 8) -- the same as shown on the graph. The negative value of 'a' tells you the parabola opens downward, so the vertex is the maximum. The maximum is 8 at x = -1.
Y=1 because on each equation it needs 1 for it to be the answer
15% of $269.99 = 0.15 x 269.99 = $40.50 (nearest cent)
Answer: $40.50
Answer:
an Injective function is a function that maps distinct elements of its domain to distinct elements of its codomain. In other words, every element of the function's codomain is the image of at most one element of its domain.
Step-by-step explanation:
Part A)
If f(x) - 3 is the new equation, it means there is a vertical translation of f(x) down 3 units. The y-intercept will decrease by 3 units. Areas of increasing on the function may be lessened as the function is being translated down 3 units. The areas of decrease will increase because the function is being translated down. End behaviour will not change from a translation as long as the function is continuous at each end, (not a finite function with end points). The evenness or oddness of f(x) will not change either.
Part B:
The y-intercept will be flipped horizontally about the x-axis and multiplied by 2. This will mean that if the y-intercept was positive, it will now be negative and vice versa. The increasing and decreasing regions of the graph will be flipped, so anywhere f(x) was positive will now be negative and vice versa. They will also be double what they were before because all values are multiplied by 2. The end behaviour will switch. If f(x) was from Quad1->Quad3 for example, it will now be Quad2->Quad4 because of the flip at the x-axis. The evenness and oddness of the function will not change seeing as the degree of f(x) is not affected.
