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ruslelena [56]
2 years ago
14

A vector starts at point ( -3, 8) and ends at point (-2, 2) what is the horizontal component of the vector?

Mathematics
2 answers:
Nitella [24]2 years ago
6 0

Using vector concepts, it is found that:

  • 1. The horizontal component of the vector is 5.
  • 2. The magnitude is of 14.87.
  • 3. The vertical component of the vector is 2.

-------------

  • A vector (x,y) has x as horizontal component and y as vertical component.
  • The magnitude is M = \sqrt{x^2 + y^2}
  • Given two points, a <em>vector </em>is formed by the subtraction of the endpoint by the start point.

-------------

Item 1:

  • The <em>horizontal component </em>of the start is -3.
  • The <em>horizontal component</em> of the end is 2.
  • Thus, the horizontal component of the vector is 2 - (-3) = 2 + 3 = 5

-------------

Item 2:

  • <em>Starts </em>at (1,9), <em>ends </em>at (6,-5), thus, the coordinates are:

(6,-5) - (1,9) = (6-1, -5 - 9) = (5, -14)

The magnitude is:

\sqrt{5^2 + (-14)^2} = \sqrt{25 + 196} = \sqrt{221} = 14.87

The magnitude is of 14.87.

-------------

Item 3:

  • The <em>vertical component </em>of the start is -10.
  • The <em>vertical component</em> of the end is -8.
  • Thus, the vertical component of the vector is 8 - (-10) = -8 + 10 = 2

A similar problem is given at brainly.com/question/24606590

irga5000 [103]2 years ago
4 0

Answer:  Hi! I'm sorry this answer is late but if you're still wondering, I think this is the answer . Please let me know if it works for you.

Step-by-step explanation:

Question 1.

So, The question asks us for the Horizontal Component.

The Horizontal component is simply 'x' in a plane coordinate or (x,y).

So, first we have to recognize the Initial and Terminal Point. For this vector it is:

Initial Point(Starting point): (-3,8) Terminal Point(End point): (-2,2).

To find components <em>given </em><u><em>the Initial and Terminal points in coordinates, </em></u>the formula is as follows: x-coordinate Terminal minus x-coordinate Initial and  y-coordinate Terminal minus y-coordinate initial. Or in other terms : (Xₜ-Xᵢ, Yₜ-Yᵢ)  

To find the Horizontal Component it would look like this:

Xₜ-Xᵢ:  -2- (-3)  -------->  -2+3 = 1 (If you're wondering why the sign changed to addition it's because 2 negative signs adjacent to each other change to addition per integer rules. An example:  -5-(-7)  -----> -5+7 ). So, 1 is your horizontal component.

Question 2.  

In order to find the magnitude of a vector, you must know the Terminal and Initial Points because Magnitude = Terminal - Initial.  

Terminal: (6, -5)    Initial: (1, 9)  

Remember the Formula (Xₜ-Xᵢ, Yₜ-Yᵢ)  

6-1 = 5   |      -5-9 = -14

We just found the horizontal and vertical components.

Now we use pythagoreans theorem to find the magnitude.

5²+-14² = c²  ------>  25+ 196 = c²  -------->  221 = c²  ------->  √ 221 =  √ c²    

c² = 14. 86606875  or 14.87 if rounded.

Question 3.

This question is asking us what the vertical component of the vector is.

Terminal: (8,-8) Initial: (-1,-10)

Remember the Formula (Xₜ-Xᵢ, Yₜ-Yᵢ)  

Vertical Component: ( -8 - (-10) -----> -8 +10 = 2

Horizontal component: (8-(-1)) ------> 8+1 = 9

Once again, I hope this helps. Sorry it took so long and I wish you all the best of luck in school. Have a blessed day.

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(9)

Expand and simplify right side and compare coefficients of like terms on left side.

(x - 2)(x² + ax + b) + c

= x³ + ax² + bx - 2x² - 2ax - 2b + c

= x³ + x²(a - 2) + x(b - 2a) - 2b + c

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b - 2a = - 3 ← substitute a = 4

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constant terms

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Thus a = 4, b = 5 and c = 14

-------------------------------------------------

(10)

Since both functions cross the x- axis at - 2 then (- 2, 0) satisfies both, that is

f(- 2) = (-2)^{4} + a(- 2)³ + b(- 2)² + 36(- 2) + 144 = 0, that is

- 16 - 8a + 4b - 72 + 144 = 0

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- 8a + 4b = - 56 → (1)

and

g(- 2) = (-2)^{4} + (a + 3)(- 2)³ - 23(- 2)² + (b + 10)(- 2) + 40 = 0, that is

- 16 - 8(a + 3) - 92 - 2(b + 10) + 40 = 0

- 16 - 8a - 24 - 92 - 2b - 20 + 40 = 0

- 8a - 2b - 112 = 0

- 8a - 2b = 112 → (2)

Subtract (1) from (2) term by term

- 6b = 168 ( divide both sides by - 6 )

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Substitute b = - 28 into (2)

- 8a + 56 = 112 ( subtract 56 from both sides )

- 8a = 56 ( divide both sides by - 8 )

a = - 7

Thus a = - 7 and b = - 28

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