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motikmotik
3 years ago
13

Please help me thanks

Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0
The answer is 1,2 and 3
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Tracey is shopping for candy for her party and needs lollipops and gummy bears for a display she is making. Lollipops are $1 per
sleet_krkn [62]
Tracey can buy 12 pounds of gummy bears. 

She bought 6 pounds of lollipops for $6, and that leaves her with $9 left to spend. If we multiply $0.75 dollars per pound by 12 pounds, we get $9. Therefore, that is the amount of bears to buy. You can also divide $9 by $0.75 and get 12 pounds.
6 0
4 years ago
You earn a new a weekly allowance of five dollars and your neighbor is paying you 7.50 per hour for shoveling the driveway how m
Leokris [45]

Answer:

Hours of work= 3.5

Step-by-step explanation:

Giving the following information:

Allowance= $5

Hourly pay= $7.5

Desired profit= $31

<u>To calculate the number of hours to work, we need to use the following formula:</u>

Hours of work= shoveling pay / hourly pay

Hours of work= (31 - 5)/7.5

Hours of work= 26/7.5

Hours of work= 3.5

6 0
3 years ago
Which graph does NOT represent a function?<br> R
vredina [299]

Answer:

The graph of the circle

Step-by-step explanation:

A function is defined to have only one output per input. Conducting the horizontal line test, we see that there are instances where the line intersects two points, which shows that some inputs have multiple outputs.

This does not fit the definition of a function.

I hope this helps! :)

5 0
3 years ago
A river 3m deep and 40 m wide is flowing at the rate 2km /h . how much water will fall into the sea in a minute.​
Alex

Answer:

Area of river = 3 × 40

= 120 {m}^{2}

amount of water that falls into the sea ⇒

= Area × rate

= 120 × 2 \frac{km}{hr}

= 120× \frac{2000  m}{60  min}

= 2 × 2000

= 4000 m  ^{3}

∴4000m  ^{3} of water falls into the sea permin.

Step-by-step explanation:

Hope it is helpful...

8 0
3 years ago
Read 2 more answers
When a jug is half-filled with marbles, it weighs 2.6 kg. If the jug weighs 4 kg when full, find the weight of the empty jug.
Soloha48 [4]

Let x be the jug, \frac{1}{2} for half-filled, y for the weight of the jug when empty.

∵ \frac{1}{2}x + y = 2.6 kg

∵ x = 4 kg

∴ \frac{1}{2} ⋅ 4 + y = 2.6 kg

∴ 2 + y =2.6 kg

∵ y = 2.6 - 2 = 0.6 kg

∴ The weight of the empty jug = 0.6 kg


8 0
3 years ago
Read 2 more answers
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