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Bezzdna [24]
3 years ago
15

Maria finds a local gym that advertises 67 training sessions for $2052. Find the cost of 153 training sessions.

Mathematics
1 answer:
Ann [662]3 years ago
7 0

Answer:

Cost\ of\ 153\ training\ sessions\ =\$4685.9\approx\$4686

Step-by-step explanation:

Cost\ of\ 67\ training\ sessions\ =\$2052\\\\Cost\ of\ 1\ training\ sessions\ =\frac{Total\ cost}{Total\ training\ sessions}\\\\Cost\ of\ 1\ training\ sessions\ =\frac{2052}{67}\\\\Cost\ of\ 153\ training\ sessions\ =153\times cost\ of\ 1\ training\ sessions\ \\\\Cost\ of\ 153\ training\ sessions\ =153\times\frac{2052}{67}=4685.9\\\\Cost\ of\ 153\ training\ sessions\ \$4685.9\approx4686

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Which of these equations have no solution? Check all that apply.
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Answer:

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The perimeter of a rectangle is 62 m. The length is four more than two times the width. What is the length?
Travka [436]
--------------------------------------------------
Define length and width
--------------------------------------------------
Let x be the width
width = x
Length = 2x + 4

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Formula
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Perimeter = 2(length + width)

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Find Length and width
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62 = 2(2x + 4 + x)
62 = 2(3x + 4)            <em> ← combine like terms  </em> 
62 = 6x + 8                 <em>← remove bracket </em>  
62 - 8 = 6x                  <em>← minus 8 on both sides </em>
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x = 54 ÷ 6                   <em>← divide by 6 on both sides</em>
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Find Length and Width
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Width = x = 9 m
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Answer: Length = 22m
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3 years ago
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Step-by-step explanation:

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3 years ago
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