Answer: a) zeros: x = {0, 4, -2}
b) as x → ∞, y → ∞
as x → -∞, y → ∞
<u>Step-by-step explanation:</u>
I think you mean (a) find the zeros and (b) describe the end behavior
(a) Find the zeros by setting each factor equal to zero and solving for x:
x (x - 4) (x + 2)⁴ = 0
- x = 0 Multiplicity of 1 --> odd multiplicity so it crosses the x-axis
- x = 4 Multiplicity of 1 --> odd multiplicity so it crosses the x-axis
- x = -2 <u>Multiplicity of 4 </u> --> even multiplicity so it touches the x-axis
Degree = 6
(b) End behavior is determined by the following two criteria:
- Sign of Leading Coefficient (Right side): Positive is ↑, Negative is ↓
- Degree (Left side): Even is same direction as right side, Odd is opposite direction of right side
Sign of the leading coefficient is Positive so right side goes UP
as x → ∞, y → ∞
Degree of 6 is Even so Left side is the same direction as right (UP)
as x → -∞, y → ∞
Answer:
3
Step-by-step explanation:
24/3 is equaled to 3
if you don't know what that means its 24 divided by 3
Answer: 12
6x2 is 12 and 12x3 is 38.
We will first find the prime factorization of 12 and 36. After we will calculate the factors of 12 and 36 and find the biggest common factor number .
The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Answer:
Step-by-step explanation:
