How do you solve 2m-10=44+8m
2 answers:
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(These steps show you how to determine whether the lines are parallel or perpendicular) -
*use the equation of straight line :
y = mx + c
*use the equation of straight line :
y = mx + c
Answer:
Step-by-step explanation:
Given that Brahmagupta’s solution to a quadratic equation of the form
involved only one solution.
we have to find the solution for the equation
is
is
Answer:
D'(-6, 0) is the image of point D(-2, 0) under a dilation about the origin (0,0) with a scale factor of 3, as shown in attache figure below.
Please check the attache graph below where you can check the plot of the image D' of point D.
Step-by-step explanation:
As the point D on the coordinate plane has the vertex location
- D(-2, 0)
The rule of dilation about the origin (0,0) with a scale factor of 3:
The rule states that if we dilate the point, let say D(-2, 0), under a dilation about the origin (0,0) with a scale factor of 3, all we need to multiple the coordinates of the point D with 3. The result will be the image of point D.
so
- P(x, y) → P'(3x, 3y)
- D(-2, 0) → D'(-6, 0) ∵ (-2×3, 0×3)=(-6, 0)
Therefore, the image of point D under a dilation about the origin (0,0) with a scale factor of 3 can be plotted at the location D'(-6, 0).
So the new location of D' is (-6, 0).
D'(-6, 0) is the image of point D(-2, 0) under a dilation about the origin (0,0) with a scale factor of 3, as shown in attache figure below.
Please check the attache graph below where you can check the plot of the image D' of point D.
