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Sphinxa [80]
3 years ago
8

Proof by mathematical induction

Mathematics
1 answer:
Ghella [55]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

I will assume that 3n is the last term.

First let  n = k, then:

Sum ( k terms) =  7k^2 + 3k

Now, the sum of k+1 terms  = 7k^2 + 3k + (k+1) th term

=  7k^2 + 3k + 14(k + 1) - 4

=   7k^2 + 17k + 10

Now 7(k + 1)^2 = 7k^2 +14 k + 7 so

7k^2 + 17k + 10

=  7(k + 1)^2  + 3k  + 3

= 7(k + 1)^2 + 3(k + 1)

Which is the  formula for the Sum of k terms with the k replaced by k + 1.

Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.

But the formula is true for 1 term because  7(1)^2 + 3(1) = 10 .

So it must also be true for all subsequent( 2,3 etc) terms.

This completes the proof.

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What is the area of this compound shape?
Paraphin [41]

Answer:

139.36

Step-by-step explanation:

first you do 8*8 because that would be the area of the square part

8*8=64

then find the area of the semicircle

first the Radis of it is 4 because 8/2=4

A=3.14R^2/2

3.14*4^2/2

3.14*16/2

50.24/2

25.12

now because there are 3 of the semicircles you do

25.12*3

75.36

then you add the 64 from the square to get your answer

75.36+64

139.36

6 0
3 years ago
What is the difference between 89 and 236 ( math equation)
inn [45]

Answer:

147

Step-by-step explanation:

236-89=147

3 0
3 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
3 years ago
BRAINIEST FOR CORRECT ANSWER!! :))) ——————-
Morgarella [4.7K]
Answer:
3 < c < 13
Step-by-step explanation:
A triangle is known to have 3 sides: Side a, Side b and Side c.
For a triangle, one of the three sides is longer than the other two sides. (The only exception is when we are told specifically that a triangle is an equilateral triangle, where all the 3 sides are equal to each other).
To solve the above question, we would be using the Triangle Inequality Theorem.
The Triangle Inequality Theorem states that the summation or addition of the lengths of any two sides of a triangle is greater than the length of the third side.
Side a + Side b > Side c
Side a + Side c > Side b
Side b + Side c > Side a
For the above question, we have 2 possible side lengths for the third side of the triangle. We are given in the above question,
side (a) = 5
side (b) = 8
Let's represent the third side as c
To solve for the above question,we would be having the following Inequality.
= b - a < c < b + a
= 8 - 5 < c < 8 + 5
= 3 < c < 13
4 0
3 years ago
Need help please. I need help with how to do these problems.
Vikki [24]
Look it up I will find it
3 0
3 years ago
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