What's the greatest common number between 5,11

Talja [164]

Answer:

B all square are regular polygons

8 0

3 years ago

Derek weighs 155 pounds and drives a utility vehicle that can carry no more than 220 pounds. He plans to use his utility vehicle

liraira [26]

By the looks of this the answer is E

Derek weighs 155
155+220

8 0

3 years ago

If 48% of a number, n, is 40.32, what is 20% of n?

jok3333 [9.3K]

Answer:

Step-by-step explanation:

48% of n = 0.48n = 40.32

n = 84

20% of n = 0.20*84 = 16.8

7 0

3 years ago

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

jolli1 [7]

First, you need to isolate the x in the first equation.
-x + 5y = 1
Subtract 5y from both sides, leaving you with the following equation:
-x = 1-5y
Because you are trying to solve for positive x and not negative x, you need to make x positive. Therefore you divide both sides by -1. In Algebra, when 1 is the coefficient of the variable, it is not shown, but it is still there. The new equation will be the following: x = 5y-1
Now you just need to substitute the x within the second equation for the x equation we just solved for.

Therefore, the right answer will be 2(5y-1)+4y= -4. Now, all you have to do is choose the answer that states exactly that, which is the first choice.

3 0

3 years ago

1. A luge race is very dangerous, and a crash can cause serious injuries. The league requires anyone who has a crash to have a t

antiseptic1488 [7]

Answer:

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

Step-by-step explanation:

For each race, there are only two possible outcomes. Either the person has a crash, or the person does not. The probability of having a crash during a race is independent of whether there was a crash in any other race. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A certain performer has an independent .04 probability of a crash in each race.

This means that $p = 0.04$

a) What is the probability she will have her first crash within the first 30 races she runs this season

This is:

$P(X \geq 1) = 1 - P(X = 0)$

When $n = 30$

We have that:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{30,0}.(0.04)^{0}.(0.96)^{30} = 0.2939$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2939 = 0.7061$

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

7 0

3 years ago