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Wewaii [24]
3 years ago
9

If angle a has the terminal ray that falls in the fourth quadrant and cosine a equals 5/9 then determine the value of sin a in s

implest radical form
Mathematics
1 answer:
Tema [17]3 years ago
8 0

Answer: -\dfrac{2\sqrt{14}}{9}

Step-by-step explanation:

Given

\cos a=\dfrac{5}{9}

a lies in the fourth quadrant

So, sine must be negative in the fourth quadrant

Using identity \sin ^2 x+\cos^2 x=1 to find sine value

\Rightarrow \sin^2 a=1-\dfrac{5^2}{9^2}

\\\\\Rightarrow \sin^2 a=1-\dfrac{25}{81}\\\\\\\Rightarrow \sin^2 a=\dfrac{56}{81}\\\\\\\Rightarrow \sin a=-\sqrt{\dfrac{56}{81}}\\\\\\\Rightarrow \sin a=-\dfrac{2\sqrt{14}}{9}

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See below

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