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3 years ago

Which multiplication has a negative answer?

Mathematics

2 answers:

yanalaym [24]3 years ago

8 0

Answer:

C) -1*-1*-1*-1*-1

Step-by-step explanation:

I don't know what you mean by eliminate but the answers to the multiplications are:

A) -1*-1 = 1

B) -1*-1*-1*-1 = 1

C) -1*-1*-1*-1*-1 = -1

D) -1*-1*-1*0 = 0

artcher [175]3 years ago

5 0

The answer is "C"
-1 × -1 × -1 × -1 × -1 × -1 = -1

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A store is instructed by corporate headquarters to put a markup of 67% on all items. An item costing 12$ is displayed by the s

Arisa [49]

Answer:

Step-by-step explanation:

12$ = original price (need to add 67% mark up)

12/100 = 0.12 = 1%

0.12 x 67 = $8.04 markup

12 + 8.04 = $20.04 is the correct selling price

the error was accidently not adding the markup ($8.04) to the original price

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3 years ago

F(x)= x^2 + 10f(x)=x 2 +10 Over which interval does fff have a positive average rate of change?

Mazyrski [523]

Answer:

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Step-by-step explanation:

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3 years ago

HELP ME ! What is the value of X

Harlamova29_29 [7]

Answer:

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3 years ago

7. Calculate the distance Derek rows his boat if he rows a mile each day for 11 days.

Bogdan [553]

If Derek rows a boat one mile for 11 days, we can solve this using the equation:

11*1=11

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I hope this helps!

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3 years ago

Two ships set sail in different directions from the same place. Tyler's ship sail 35 miles while Noah's ship sails for 42 miles.

earnstyle [38]

Answer:

The angle between their paths when they started is 93°.

Step-by-step explanation:

The Law of Cosines

It relates the length of the sides of a triangle with one of its internal angles.

Let a,b, and c be the length of the sides of a given triangle, and x the included angle between sides a and b, then the following relation applies:

$c^2=a^2+b^2-2ab\cos x$

When the two ships travel in different directions from the same point in the plane, they form an angle we called x in the image below.

Tyler's ship sails a=35 miles and Noah's ship sails for b=42 miles. At some time they are c=56 miles apart.

Since we know the values of all three side lengths, we solve the equation for x:

$\displaystyle \cos x=\frac{a^2+b^2-c^2}{2ab}$

Substituting values:

$\displaystyle \cos x=\frac{35^2+42^2-56^2}{2(35)(42)}$

Calculating:

$\displaystyle \cos x=-\frac{147}{2940}=-\frac{1}{20}$

Computing the inverse cosine:

$x = \arccos(-0.05)$

$x \approx 93^\circ$

The angle between their paths when they started is 93°.

6 0

3 years ago