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Doss [256]
3 years ago
13

Which multiplication has a negative answer?

Mathematics
2 answers:
yanalaym [24]3 years ago
8 0

Answer:

C) -1*-1*-1*-1*-1

Step-by-step explanation:

I don't know what you mean by eliminate but the answers to the multiplications are:

A) -1*-1 = 1

B) -1*-1*-1*-1 = 1

C) -1*-1*-1*-1*-1 = -1

D) -1*-1*-1*0 = 0

artcher [175]3 years ago
5 0
The answer is "C"
-1 × -1 × -1 × -1 × -1 × -1 = -1
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First six shipments:
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For problems like this, we need to find the pattern between the set of numbers to create a general equation for f(x). Given that x is the shipment number, let us first observe the first six shipments' behavior.
1  10 |
2  16 = 10 + 1(6) |
3  22 = 10 + 2(6) |
4  28 = 10 + 3(6)|  
5  34 = 10 + 4(6) |
6  40 = 10 + 5(6) |

From these, we can observe that given x number of shipments, the total number of objects would be 10 + (x-1)6 = 10 + 6x - 6 = 6x +4. Thus, given f(x), we have 

f(x) = 6x + 4
Answer: f(x) = 6x + 4

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3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
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