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slamgirl [31]
3 years ago
11

Cel mai mic numar impar rotunjit la mii

Mathematics
1 answer:
Aleks [24]3 years ago
7 0
I have no idea what u said XD
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Factor x2 − 4x + 5.<br><br> Prime<br> (x + 5)(x − 1)<br> (x − 5)(x − 1)<br> (x + 5)(x + 1)
crimeas [40]
1) Prime
<span>2) (x + 5)(x − 1) = x²-1x+5x-5= x²+4x-5
3) (x − 5)(x − 1)= x² -1x -5x +5= x² -6x +5
4) (x + 5)(x + 1) = x² +1x +5x+ 5x = x² +6x+5

It is 1) Prime


</span>
8 0
3 years ago
Plz help!!<br> number 16 goes also with the bottom
Andreyy89
The answer is D because 4 of the sides have the demension of 3 by 2 and 2 sides have the demension of 2 by 2.
5 0
4 years ago
Read 2 more answers
n many population growth problems, there is an upper limit beyond which the population cannot grow. Many scientists agree that t
givi [52]

Answer:

\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})

Step-by-step explanation:

The logistic function of population growth, that is, the solution of the differential equation is as follows:

P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}

We use this equation to find the value of r.

In this problem, we have that:

K = 16, P_{0} = 2, P(50) = 4

So we find the value of r.

P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}

4 = \frac{16*2e^{50r}}{16 + 2*(e^{50r} - 1)}

4 = \frac{32e^{50r}}{14 + 2e^{50r}}

56 + 8e^{50r} = 32e^{50r}}

24e^{50r} = 56

e^{50r} = 2.33

Applying ln to both sides of the equality

50r = 0.8459

r = 0.017

So

The differential equation is

\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})

3 0
3 years ago
Looking for the number that belongs to X
tester [92]

Answer:

60 should be your answer

3 0
4 years ago
What are the solutions of the quadratic equation 50-x^2=0
Licemer1 [7]
Helloo

Use the quadratic formula to find the solutions.<span><span><span>−b±<span>√<span><span>b2</span>−4<span>(ac)</span></span></span></span><span>2a</span></span><span><span>-b±<span><span>b2</span>-4<span>(ac)</span></span></span><span>2a</span></span></span>Substitute the values <span><span>a=−1</span><span>a=-1</span></span>, <span><span>b=0</span><span>b=0</span></span>, and <span><span>c=50</span><span>c=50</span></span> into the quadratic formula and solve for <span>xx</span>.<span><span><span>0±<span>√<span><span>02</span>−4⋅<span>(−1⋅50)</span></span></span></span><span>2⋅−1</span></span><span><span>0±<span><span>02</span>-4⋅<span>(-1⋅50)</span></span></span><span>2⋅-1</span></span></span>Simplify.<span><span>x=±5<span>√2</span></span><span>x=±52</span></span>The result can be shown in both exact and approximate form.<span><span>x=±5<span>√2</span></span><span>x=±52</span></span><span>x≈7.07106781,−<span>7.07106781

Have a nice day</span></span>
8 0
4 years ago
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