Eight times the quantity of a number and six.
8 (x+6)
9514 1404 393
Answer:
zero
Step-by-step explanation:
Dividing the second equation by -3, it becomes ...
x -3y = 7/3
Compared to the first equation, ...
x -3y = 5
we see that it is <em>inconsistent</em>. No values of the variables can satisfy both equations. There are no solutions.
Answer:
D
Step-by-step explanation:
Interesting question. The wording is a bit awkward. I think you have to assume the base is a square and each succeeding base is also a square.
So the first thing to do is to add the bases together.
30*30 + 23*23 + 16*16 + 9*9
Don't add these -- not yet.
Now take the height into consideration
6 *(30*30 + 23*23 + 16*16 + 9*9)
The point is that you only have to multiply by 6 once.
6*(900 + 529 + 256 + 81)
6*(1766)
10596 cubic inches
The answer is D
You can get the tens digit of any number <em>n</em> by computing the quotient
(<em>n</em> (mod 100)) / 10
and ignoring the remainder.
Taking the given sum (mod 100) gives
7! + 8! + … + 2006! ≡ 7! + 8! + 9! (mod 100)
since the last 1997 terms (i.e. 10! up to 2006!) in the sum are multiples of 100. That is,
• every term beyond 100! is obviously a multiple of 100
• every term beyond 25! contains a factor of both 4 and 25
• every term beyond 10! contains two factors each of both 2 and 5 (i.e. every factorial term contains 4, 5, and 10)
The remaining sum is easy to compute by hand:
7! + 8! + 9! = 7! (1 + 8 + 8 × 9) = 5040 × 81 = 408,240
so the tens digit is 4.
