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klio [65]
2 years ago
15

A 84-inch television has a screen that is 41.5-inches tall. How wide is the screen?

Mathematics
2 answers:
tatuchka [14]2 years ago
8 0

Answer:

3486 in.

Step-by-step explanation:

84 x 41.5

=

3486 in. converted to ft. is 24.2083 ft.

Why is this Television so big?

GaryK [48]2 years ago
3 0
39.5 is the answer it’s basically just mental math
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When you were born, your uncle put $1000 into a bank account for you. According to the terms of the account, your investment
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Answer:

D. Time; amount;  $2800

I hope this is right because I was looking for the answer to the same question and this is the solution I came up with.

Step-by-step explanation:

Time is the independent variable because it is the variable that is changed.

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If she spent a total of $44.25 on fabric, what was the cost per yard? She bought 14 3/4. Explain how you solved
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44.25 \div 14.75 = 3
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3 years ago
kayla is drawing a picture of her favorite building in her city, the height of the building on her drawing is 3 inches tall, the
Stolb23 [73]

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1/12

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4 0
3 years ago
A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for
Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

\implies h=\frac{1}{w^2}

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

= 2\times \frac{1}{w^2}(w+2w)

=\frac{6w}{w^2}

=\frac{6}{w}  

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}

=2w^2+4w^2+\frac{12}{w}

=6w^2+\frac{12}{w}

Differentiating with respect to w,

C'(w) = 12w -\frac{12}{w^2}

Again differentiating with respect to w,

C''(w) = 12 + \frac{24}{w^3}

For maxima or minima,

C'(w) = 0

\implies 12w -\frac{12}{w^2}=0

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w^3-1=0\implies w = 1

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0
3 years ago
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