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3 years ago

Using at least three sentences, describe the process of weathering, and explain how it can happen physically or chemically.

Geography

2 answers:

Fittoniya [83]3 years ago

8 0

Answer:

Synthetic weathering breaks down or rots rocks and minerals. A case of this is water and limestone.

Explanation:

Natural weathering happens when plant separate rocks. One the stone has been debilitated and separated it is prepared for Erosion. This happens when rocks are grabbed and move as a rule by water. Mechanical weathering separates shakes, this normally happens when water gets into splits, solidifies and extends the stone.

Snowcat [4.5K]3 years ago

6 0

Chemical weathering decomposes or decays rocks and minerals. An example of this is water and limestone. Organic weathering happens when plant break up rocks. One the rock has been weakened and broken up it is ready for Erosion. This happens when rocks are picked up and move usually by water. Mechanical weathering breaks up rocks, this usually happens when water gets into cracks, freezes and expands the rock. Hope this helps <3

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3 years ago

Using Wien’s Law, estimate the wavelength at which these common materials radiate their peak brightness (show your work):

SSSSS [86.1K]

Explanation:

Wien’s Law:

$\lambda _{max}\propto \frac{1}{temperature}$

The law states that the wavelength at which black body emits maximum heat is inversely proportional to the temperature of the body in Kelvins.

$\lambda _{max}=\frac{2.9\times 10^{-3}}{T}$

1) Walls at 300 K

$\lambda _{max}=\frac{2.9\times 10^{-3} mK}{300 K}$

$\lambda _{max}=9.666\times 10^{-6} m$

2) Ice water at 273 K :

$\lambda _{max}=\frac{2.9\times 10^{-3} mK}{273 K}$

$\lambda _{max}=1.062\times 10^{-5} m$

3) Hot water at 373 K :

$\lambda _{max}=\frac{2.9\times 10^{-3} mK}{373 K}$

$\lambda _{max}=7.775\times 10^{-6} m$

4)Skin at 310 K:

$\lambda _{max}=\frac{2.9\times 10^{-3} mK}{310 K}$

$\lambda _{max}=9.355\times 10^{-6} m$

5)An incandescent light bulb at 3000 K

$\lambda _{max}=\frac{2.9\times 10^{-3} mK}{3000 K}$

$\lambda _{max}=9.666\times 10^{-7} m$

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Answer:

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