Your answer would be B, $12/ 1 hour
The distance from the center of dilation, P, to.the image vertice S' is; 6 units.
<h3>What is the distance from the center of dilation, P, to the image S'?</h3>
It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.
Hence, since the dilation factor as given in the task content is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6units.
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Answer:
A. -25x + 7
Step-by-step explanation:
First, to answer this question, we will combine the two sides of the equation:
(-9x + 13) + (-16x - 6)
Now, we take away the parentheses and add like terms:
-9x + 13 + -16x - 6 =
-25x + 7
So, the answer would be A. -25x + 7
Hope this helps :)
Answer:
C. 3.4 feet
Step-by-step explanation:
Let, the amount of increase be 'x' feet.
As, the length and width of the garden are 20 ft and 12 ft respectively.
It is given that the area of the new garden is 360 ft²
Since, the length and width are increased by 'x'.
The new length and width are (x+20) ft and (x+12) ft respectively.
So, we get,
New area, = length × breadth = (x+20) × (x+12)
i.e. 360 =
i.e.
i.e. (x+35.4)(x-3.4)=0
i.e. x = -35.4 and x= 3.4
Since, the value of x cannot be negative.
Thus, x = 3.4 feet.