It similar Because there both in the 2s
Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.
For example, if you have
... u'' + a·u' + b·u = f
you can define u1 = u, u2 = u' and now you have the system
... (u2)' + a·u2 + b·u1 = f
... (u1)' = u2
Rearranging, this is
... (u1)' = u2
... (u2)' = f - a·u2 - b·u1
ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.
Answer:
1/4
Step-by-step explanation:
Assuming the number cube is a six-faced die, you have
1 <u>2</u> 3 <u>4</u> 5 <u>6</u>
three odd numbers, and three even numbers. Therefore, the chance of it landing on an odd number or even number is 3/6, which equals 1/2. <em>That means you have a 50% chance to get an odd number, or an even number.</em>
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So, you have two die. Both have a 50/50 chance of getting an even or odd number. So what's the chance of one landing on an odd number, and the other landing on an even number?
- You would have a 25% chance for an <u>even</u> and then an <u>even</u> number
- You would have a 25% chance for an <u>odd</u> and then an <u>odd</u> number
- You would have a 25% chance for an <u>even</u> and then an <u>odd</u> number
- You would have a 25% chance for an <u>odd</u> and then an <u>even</u> number.
25% as a simplified fraction is 1/4. Therefore, 1/4 is your answer.
Answer:
1.28 or 912/715
Step-by-step explanation:
sine= opposite side/hypotenuse
cos=adjacent/ hypotenuse
sine a= 12/13 using the Pythagorean Theorem and solve for the missing side. (which is the adjacent side)
cos a = 5/13
Do the same for sine b
cos b= 9.8/11
add both the cosine value
(5/13)+(9.8/11)=1.28 or 912/715 in fraction form
Answer:
my answer for y is -6, x is -10
Step-by-step explanation:
just eliminate the -4s by subtracting them and you will get the value of y.
now you can use either eqn (I) or (ii) which are first and second.
anyone you decide to choose just replace y by the value you got and you will get the value of x.
pls try to do it buddy you can
