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spayn [35]
3 years ago
5

4-50:

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0
X=3 and y=5. To solve the system algebraically, I think you just have to plug in the answers. I'm not quite sure for (b)
You might be interested in
Sonia walks to her aunt's house. She leaves home at 1025. She walks a total of 12km at an average speed of 5km/h. Work out the t
lisabon 2012 [21]

Answer: 1249 hrs

Step-by-step explanation:

Sophia walked for 12 km to get to her aunt's house.

She did this at a speed of 5km/h which means that the time taken was:

Time = Distance / Speed

= 12 / 5

= 2.4 hours

2.4 in hours:

= 0.4 * 60 minutes

= 24 minutes

= 2 hours 24 minutes

If she left at 1025, she would arrive at:

= 1025 + 2 hours 24

= 1249 hrs

3 0
3 years ago
one number is equal to the square of another. find the numbers if both are positive and their sum is 1122
statuscvo [17]

Answer:

One number is 561

The other number is 23.6854

Step-by-step explanation:

x = y^2                One number = the square of another

x + y^2 = 1122     The sum of the two numbers is 1122

Substitute y^2 in for x on the second equation.

y^2 + y^2 = 1122    Combine like terms on the left

2y^2 = 1122            Divide by 2

y^2 = 1122/2

y^2 = 561                Take the square root of both sides.

y = 23.6854            

x = y^2

x = 561

y^2 = 561


4 0
3 years ago
The principal observes 8th grade the following day. Of the 120 students, 42 brought their lunch from home, 72 purchased lunches,
Rama09 [41]

Answer:

i pretty sure i do not know that answer to be honest

Step-by-step explanation:

i believe this because i dont know anything about this im still lost

8 0
2 years ago
1. The sum of the three consecutive members of the geometric sequence is 13. The proportion of the third and the first member is
aev [14]
If a = first term and r = common ratio we have

a + ar + ar^2 = 13   and ar^2 / a = r^2 = 9

so r = 3

and a + 3a + 9a = 13 
so a = 1

so they are  1,3 and 9 

2.
in geometric series we have

4 , 4r ,4r^2 , 60

Arithmetic;
 4,  4r , 4r + d ,  4r + 2d

so we have the system of equations
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30 
so d = 30 - 2r 
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0

2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r  = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24

and the numbers are 4*3 =  12 , 4*3^2 = 36

first 3  are  4 , 12 and 36  ( in geometric)
and last 3 are 12, 36 and 60  ( in arithmetic)

The 2 numbers we ause are 12 and 36.





7 0
3 years ago
Simplify the rational expression.  State any restrictions on the variable.
AveGali [126]

Answer:

The last choice.

Step-by-step explanation:

\dfrac{k^2-k-2}{k^2-4k-5}=\dfrac{(k+1)(k-2)}{(k+1)(k-5)}=\dfrac{k-2}{k-5}

The value of k must be restricted from being one that makes the original denominator zero. Hence k ≠ -1 or 5.

7 0
2 years ago
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