Given :
Initial length of electric cable needed, 
.
Later, Sally is told that the homeowner has decide to cut back from a three-car garage to a two-car garage, which will eliminate two branch circuits, one of 23 feet and the other of 34 feet.
To Find :
How many feet of wire will be needed now.
Solution :
Wire needed is given by :
Required = Total wire - ( length of 1nd branch + length of 2nd branch )
Required = 550 - ( 23 + 34 )
Required = 550 - ( 57 ) ft
Required = 443 ft
Therefore, length of wire required is 443 ft.
Hence, this is the required solution.
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Please, give me some minutes to take over your question
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Rate = miles / time
8/t = 7/ 35
Dividing by 7
8/t = 7/ 35
8/ 7t = 1/ 35
Multiplying by t
8/7 = t/35
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Options
1) 8/t = 35/ 7 (False, t/8 = 35/ 7 )
2) t/8 = 7/ 35 (False, t/8 = 35/ 7 )
3) 8/7 = t/ 35 (TRUE)
4) 7/8 = t/35 (False, 8/7 = t/ 35 )
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Answer
3) 8/7 = t/ 35 (TRUE)
Answer:
From your question, I am assuming you are talking about an absolute value graph. In this case the answer would be y = |2 + 6|
Step-by-step explanation: Always remember, when you are graphing absolute value graphs:
When you shift left or right, you put the amount you are shifting inside the absolute value sign.
When you are shifting up or down, you put the amount you are shifting outside the absolute value sign.
When shifting left on a graph, you usually think of subtraction. However, when dealing with absolute value graphs, when you are shifting left, you use addition, as you can see in this problem.
The same goes for right. You use subtraction when shifting right, contrary to what you may think.
However, when you go up, you still use addition, and when you shift down, you still use subtraction.
Answer:
b. 9/100
Step-by-step explanation:
It helps if you have memorized the cubes of small integers. Of course, the ones needed here are ...
3³ = 27
10³ = 1000
The desired value can be simplified to ...
![\left(-\dfrac{1000}{27}\right)^{-2/3}=\left(-\sqrt[3]{\dfrac{3^3}{10^3}}\right)^2=\dfrac{(-3)^2}{10^2}=\dfrac{9}{100}](https://tex.z-dn.net/?f=%5Cleft%28-%5Cdfrac%7B1000%7D%7B27%7D%5Cright%29%5E%7B-2%2F3%7D%3D%5Cleft%28-%5Csqrt%5B3%5D%7B%5Cdfrac%7B3%5E3%7D%7B10%5E3%7D%7D%5Cright%29%5E2%3D%5Cdfrac%7B%28-3%29%5E2%7D%7B10%5E2%7D%3D%5Cdfrac%7B9%7D%7B100%7D)
