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Andrei [34K]
3 years ago
8

Kieran’s wallet contains 7 bills: three $5 bills, two $10 bills, one $20 bill, and one $100 bill. If Kieran pulls out two bills

at random, what is the probability that he selects exactly two $5 bills?
Use complete sentences to explain the probability. In your final answer, include all of your calculations.
Mathematics
2 answers:
Vladimir79 [104]3 years ago
8 0
3/7
3 \div 7
Setler79 [48]3 years ago
3 0

Answer:

The answer is 1/7.

Step-by-step explanation:

So, basically, 7 bills, and there is a 3/7 chance to collect 1. Another 1/3 to collect another one, which is actually 1/7.

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In the Accompanying diagram of circle O, chords AB and CD intersect at E, mAC=50 and mBD =150. Find m
galina1969 [7]

Answer:

80

Step-by-step explanation:

3 0
3 years ago
Which graph could potentially have a correlation coeffiecient (r value) of 0.95?
Masteriza [31]

Answer:

C,

Step-by-step explanation:

A and D is incorrect because they are negative correlation

and B is incorrect because a correction of 0.95 means all values are close to each other, but B values are scattered much more that C values

so answer C

3 0
2 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
2 years ago
Use the net to find the surface area of the prism.​
Naddik [55]
286 feet; use the numbers and find the area of each rectangle, then add them all together.
3 0
2 years ago
Let A = Aaron's age today and M = Maria's age today.
kondor19780726 [428]

Aaron is 4 years and Maria is 14 years old.

A = Aaron's age today

M = Maria's age today.

a. The equation based on the statement given will be:

M = A + 10

b. Maria's age based on the statement in 6 years will be:

= (A + 10) + 6

= A + 16

c. Based on the information above, the equation to solve their ages will be:

A + 16 = 2(A + 6)

A + 16 = 2A + 12

Collect like terms

2A - A = 16 - 12

A = 4

Therefore, Aaron is 4 and Maria is 14 years.

Read related link on:

brainly.com/question/22866879

3 0
3 years ago
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