Answer:
315 miles
Step-by-step explanation:
You have to multiply 4.5 hours times 70 miles
A)
Note that there are only two numbers that correspond complete wording of question: 59 and 68
It is easy to verify that the number found number is 68:
Look:
6 + 8 = 14 and
<span>86 - 68 = 18
b)
Now you can solve one system:
x + y = 21
x - y = 5
Add both equations:
2x = 26
x = 13
So: y = 8
</span>
M= movie cost
v= video cost
Create two equations with the given information. Solve for one variable in equation one. Use that answer to substitute into equation two.
2m+12v=$44
5m+3v=$29
Solve for one variable in equation 1:
2m+12v=44
Subtract 12v from both sides
2m=44-12v
Divide both sides by 2
m=(44-12v)/2
Substitute m answer in equation two:
5m+3v=$29
5((44-12v)/2)+3v=29
(220-60v)/2+3v=29
Multiply everything by 2 to eliminate the fraction
(2)(220-60v)/2+(2)(3v)=(2)(29)
220-60v+6v=58
220-54v=58
Subtract both sides by 220
-54v= -162
Divide both sides by -54
v= $3.00 cost per video
Substitute v value to find m value:
2m+12v=$44
2m+12(3.00)=44
2m+36=44
Subtract both sides by 36
2m=8
Divide both sides by 2
m=$4.00 cost per movie
Check:
5m+3v=$29
5(4.00)+3(3.00)=29
20.00+9.00=29
29=29
Hope this helps! Please mark me as brainliest if it does. :)
Answer:
-6
Step-by-step explanation:
to find slope by counting you just count rise over run
to get from (1,-4) to (0,2) you must go up 6 and back 1
6/-1 (negative cause you went back)
By the Stolz-Cesaro theorem, this limit exists if
also exists, and the limits would be equal. The theorem requires that
be strictly monotone and divergent, which is the case since
.
You have
so we're left with computing
This can be done with the help of Stirling's approximation, which says that for large
,
. By this reasoning our limit is
Let's examine this limit in parts. First,
As
, this term approaches 1.
Next,
The term on the right approaches
, cancelling the
. So we're left with
Expand the numerator and denominator, and just examine the first few leading terms and their coefficients.
Divide through the numerator and denominator by
:
So you can see that, by comparison, we have
so this is the value of the limit.