What is the point on the line given the equation y = 3(x - 4) + 5?
2 answers:
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Conversion from gallons to quarts
1 gallon = 4 quarts
Now,
Angela has
gallons = 
= 10 quarts of blue paint
Ryou has 1/2 of what Angela has = 1/2*10 = 5 quarts of white paint.
Each wall requires
of paint.
After coloring;
Blue colored walls = (10)/() = 3 walls with 7/11 quarts of paint remaining.
White colored walls = (5)/() = 1 wall with 9/11 quarts of paint remaining
1 gallon = 4 quarts
Now,
Angela has
Ryou has 1/2 of what Angela has = 1/2*10 = 5 quarts of white paint.
Each wall requires
After coloring;
Blue colored walls = (10)/(
White colored walls = (5)/(
This type of problems are solved by partitioning the figure into rectangles, whose areas we can find easily.
Picture 1)
From the point denoted by E, draw two altitudes towards the sides AG and AC.
Since ED is 3, then BC is 3. Thus, AB=4-3=1.
Since EF is 1, then HG is 1, so AH=3-1=2.
The area of the figure is equal to the area of rectangle ACDH + the area of the square HEFG.
That is, the area of the figure is 4*2+1*1=8+1=9 (square in).
Picture 2)
As in the first part, draw the altitudes EB and EH from point E.
GF is 5, so AB is 5. This means that BC=7-5=2 (in).
FE is 3, so GH is 3, that is HA=6-3=3.
Thus, Area(figure)=Area(ABFG)+Area(BCDE)=5*6+2*3=30+6=36 (square in.)
Answer: 9 (square in); 36 (square in.)
Picture 1)
From the point denoted by E, draw two altitudes towards the sides AG and AC.
Since ED is 3, then BC is 3. Thus, AB=4-3=1.
Since EF is 1, then HG is 1, so AH=3-1=2.
The area of the figure is equal to the area of rectangle ACDH + the area of the square HEFG.
That is, the area of the figure is 4*2+1*1=8+1=9 (square in).
Picture 2)
As in the first part, draw the altitudes EB and EH from point E.
GF is 5, so AB is 5. This means that BC=7-5=2 (in).
FE is 3, so GH is 3, that is HA=6-3=3.
Thus, Area(figure)=Area(ABFG)+Area(BCDE)=5*6+2*3=30+6=36 (square in.)
Answer: 9 (square in); 36 (square in.)